3.83 \(\int x \cos ^{-1}(a x)^{3/2} \, dx\)

Optimal. Leaf size=89 \[ \frac {3 \sqrt {\pi } S\left (\frac {2 \sqrt {\cos ^{-1}(a x)}}{\sqrt {\pi }}\right )}{32 a^2}-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2} \]

[Out]

-1/4*arccos(a*x)^(3/2)/a^2+1/2*x^2*arccos(a*x)^(3/2)+3/32*FresnelS(2*arccos(a*x)^(1/2)/Pi^(1/2))*Pi^(1/2)/a^2-
3/8*x*(-a^2*x^2+1)^(1/2)*arccos(a*x)^(1/2)/a

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Rubi [A]  time = 0.18, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {4630, 4708, 4642, 4636, 4406, 12, 3305, 3351} \[ \frac {3 \sqrt {\pi } S\left (\frac {2 \sqrt {\cos ^{-1}(a x)}}{\sqrt {\pi }}\right )}{32 a^2}-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2} \]

Antiderivative was successfully verified.

[In]

Int[x*ArcCos[a*x]^(3/2),x]

[Out]

(-3*x*Sqrt[1 - a^2*x^2]*Sqrt[ArcCos[a*x]])/(8*a) - ArcCos[a*x]^(3/2)/(4*a^2) + (x^2*ArcCos[a*x]^(3/2))/2 + (3*
Sqrt[Pi]*FresnelS[(2*Sqrt[ArcCos[a*x]])/Sqrt[Pi]])/(32*a^2)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 3305

Int[sin[(e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Sin[(f*x^2)/d], x], x,
Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 4406

Int[Cos[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[E
xpandTrigReduce[(c + d*x)^m, Sin[a + b*x]^n*Cos[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0]
&& IGtQ[p, 0]

Rule 4630

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*(a + b*ArcCos[c*x])^n)/(m
+ 1), x] + Dist[(b*c*n)/(m + 1), Int[(x^(m + 1)*(a + b*ArcCos[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; Fre
eQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 4636

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> -Dist[(c^(m + 1))^(-1), Subst[Int[(a + b*
x)^n*Cos[x]^m*Sin[x], x], x, ArcCos[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]

Rule 4642

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> -Simp[(a + b*ArcCos[c*x])
^(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0] && NeQ[n,
-1]

Rule 4708

Int[(((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcCos[c*x])^n)/(e*m), x] + (Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m
- 2)*(a + b*ArcCos[c*x])^n)/Sqrt[d + e*x^2], x], x] - Dist[(b*f*n*Sqrt[1 - c^2*x^2])/(c*m*Sqrt[d + e*x^2]), I
nt[(f*x)^(m - 1)*(a + b*ArcCos[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rubi steps

\begin {align*} \int x \cos ^{-1}(a x)^{3/2} \, dx &=\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {1}{4} (3 a) \int \frac {x^2 \sqrt {\cos ^{-1}(a x)}}{\sqrt {1-a^2 x^2}} \, dx\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}-\frac {3}{16} \int \frac {x}{\sqrt {\cos ^{-1}(a x)}} \, dx+\frac {3 \int \frac {\sqrt {\cos ^{-1}(a x)}}{\sqrt {1-a^2 x^2}} \, dx}{8 a}\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {3 \operatorname {Subst}\left (\int \frac {\cos (x) \sin (x)}{\sqrt {x}} \, dx,x,\cos ^{-1}(a x)\right )}{16 a^2}\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {3 \operatorname {Subst}\left (\int \frac {\sin (2 x)}{2 \sqrt {x}} \, dx,x,\cos ^{-1}(a x)\right )}{16 a^2}\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {3 \operatorname {Subst}\left (\int \frac {\sin (2 x)}{\sqrt {x}} \, dx,x,\cos ^{-1}(a x)\right )}{32 a^2}\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {3 \operatorname {Subst}\left (\int \sin \left (2 x^2\right ) \, dx,x,\sqrt {\cos ^{-1}(a x)}\right )}{16 a^2}\\ &=-\frac {3 x \sqrt {1-a^2 x^2} \sqrt {\cos ^{-1}(a x)}}{8 a}-\frac {\cos ^{-1}(a x)^{3/2}}{4 a^2}+\frac {1}{2} x^2 \cos ^{-1}(a x)^{3/2}+\frac {3 \sqrt {\pi } S\left (\frac {2 \sqrt {\cos ^{-1}(a x)}}{\sqrt {\pi }}\right )}{32 a^2}\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 64, normalized size = 0.72 \[ \frac {3 \sqrt {\pi } S\left (\frac {2 \sqrt {\cos ^{-1}(a x)}}{\sqrt {\pi }}\right )-2 \sqrt {\cos ^{-1}(a x)} \left (3 \sin \left (2 \cos ^{-1}(a x)\right )-4 \cos ^{-1}(a x) \cos \left (2 \cos ^{-1}(a x)\right )\right )}{32 a^2} \]

Antiderivative was successfully verified.

[In]

Integrate[x*ArcCos[a*x]^(3/2),x]

[Out]

(3*Sqrt[Pi]*FresnelS[(2*Sqrt[ArcCos[a*x]])/Sqrt[Pi]] - 2*Sqrt[ArcCos[a*x]]*(-4*ArcCos[a*x]*Cos[2*ArcCos[a*x]]
+ 3*Sin[2*ArcCos[a*x]]))/(32*a^2)

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccos(a*x)^(3/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [A]  time = 1.12, size = 129, normalized size = 1.45 \[ \frac {3 \, i \sqrt {\arccos \left (a x\right )} e^{\left (2 \, i \arccos \left (a x\right )\right )}}{32 \, a^{2}} + \frac {\arccos \left (a x\right )^{\frac {3}{2}} e^{\left (2 \, i \arccos \left (a x\right )\right )}}{8 \, a^{2}} - \frac {3 \, i \sqrt {\arccos \left (a x\right )} e^{\left (-2 \, i \arccos \left (a x\right )\right )}}{32 \, a^{2}} + \frac {\arccos \left (a x\right )^{\frac {3}{2}} e^{\left (-2 \, i \arccos \left (a x\right )\right )}}{8 \, a^{2}} - \frac {3 \, \sqrt {\pi } i \operatorname {erf}\left ({\left (i - 1\right )} \sqrt {\arccos \left (a x\right )}\right )}{64 \, a^{2} {\left (i - 1\right )}} + \frac {3 \, \sqrt {\pi } \operatorname {erf}\left (-{\left (i + 1\right )} \sqrt {\arccos \left (a x\right )}\right )}{64 \, a^{2} {\left (i - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccos(a*x)^(3/2),x, algorithm="giac")

[Out]

3/32*i*sqrt(arccos(a*x))*e^(2*i*arccos(a*x))/a^2 + 1/8*arccos(a*x)^(3/2)*e^(2*i*arccos(a*x))/a^2 - 3/32*i*sqrt
(arccos(a*x))*e^(-2*i*arccos(a*x))/a^2 + 1/8*arccos(a*x)^(3/2)*e^(-2*i*arccos(a*x))/a^2 - 3/64*sqrt(pi)*i*erf(
(i - 1)*sqrt(arccos(a*x)))/(a^2*(i - 1)) + 3/64*sqrt(pi)*erf(-(i + 1)*sqrt(arccos(a*x)))/(a^2*(i - 1))

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maple [A]  time = 0.17, size = 64, normalized size = 0.72 \[ \frac {8 \arccos \left (a x \right )^{2} \cos \left (2 \arccos \left (a x \right )\right )+3 \sqrt {\pi }\, \sqrt {\arccos \left (a x \right )}\, \mathrm {S}\left (\frac {2 \sqrt {\arccos \left (a x \right )}}{\sqrt {\pi }}\right )-6 \arccos \left (a x \right ) \sin \left (2 \arccos \left (a x \right )\right )}{32 a^{2} \sqrt {\arccos \left (a x \right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*arccos(a*x)^(3/2),x)

[Out]

1/32/a^2*(8*arccos(a*x)^2*cos(2*arccos(a*x))+3*Pi^(1/2)*arccos(a*x)^(1/2)*FresnelS(2*arccos(a*x)^(1/2)/Pi^(1/2
))-6*arccos(a*x)*sin(2*arccos(a*x)))/arccos(a*x)^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*arccos(a*x)^(3/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x\,{\mathrm {acos}\left (a\,x\right )}^{3/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*acos(a*x)^(3/2),x)

[Out]

int(x*acos(a*x)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x \operatorname {acos}^{\frac {3}{2}}{\left (a x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*acos(a*x)**(3/2),x)

[Out]

Integral(x*acos(a*x)**(3/2), x)

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